The sum of the interior angle of pentagon can be calculated as,
(2n−4)×90∘ = (2×5−4)×90∘ = 6×90∘
We get,=540∘
The sum of interior angles of pentagon=540∘
27x=540∘
x=540∘/27
We get,
x=20∘
Thus, each angle,5x = 5×20∘ = 100∘
4x = 4×20∘ = 80∘
7x = 7×20∘ = 140∘
6x = 6×20∘ = 120∘
Therefore, all the angles of a pentagon are 100∘,80∘,100∘,140∘ and 120∘