Question

If ∝–particle and proton are accelerated through the same potential difference, then the ratio of de Brogile wavelength of ∝–particle and proton is………….. 

(A) (1 / √2) 

(B) √2 

(C) {1 / (2√2)} 

(D) 2√2

Answer 1

The correct option is (C) {1 / (2√2)}.

Explanation:

Here h, c are constant given.

Potential difference V is given to be constant

K = Kinetic energy = qV