Question

Solve by matrix method:

2x+3y+3z=5;

x−2y+z=−4;

3x−y−2z=3

Answer 1

Given system of linear equations are 

2x + 3y + 3z = 5

x − 2y + z = −4

3x − y − 2z = 3.

Represent it in matrix form

∴ A^-1 exists

To find adjoint of A

A₁₁​ = 5,A₁₂​ = 5,A₁₃ ​= 5

A₂₁​ = 3,A₂₂​ = −13,A_23​ = 11

A_31​ = 9,A₃₂​ = 1,A₃₃​ = −7

Hence, x = 1, y = 2 and z = -1