+2 votes
in Physics by (51.4k points)
edited by

A light ray enters from medium A to medium B as shown in Figure 10.2. The refractive index of medium B relative to A will be

(a) greater than unity
(b) less than unity
(c) equal to unity
(d) zero

1 Answer

+2 votes
by (261k points)
selected by
Best answer

(a) greater than unity

Since light rays in medium B goes towards normal. So it has greater restrictive index and lesser velocity of light with respect to medium A. So refractive index of medium B with respect to medium A is greater than unity.

by (10 points)
edited by
it will be option "a"
Refractive index B wrt A =  nBA = V1/V2  = Speed of light in medium A / speed of light in medium B
Since ray of light bends towards the normal, when it goes from medium A to medium B, therefore, medium A is rarer and medium B is denser, speed in rarer medium (v1) is greater than the speed of light in denser medium (v2) ,so  V1 > V2(improper fraction), hence nBA > 1

n21 greater then 1
i.e V1>V2
then optical density M1 is rarer (A),
M2 is denser.
then bending of ray towards the normal
Conclusion :- Greater the value of RI more is bending towards normal

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.