Let p(n) : 1 + 4 +7 + ..+ (3n - 2) = \(\frac{n(3n-1)}{2}\)
Put n = 1
LHS = 1
RHS = \(\frac{1(3-1)}{2}=1\)
∴ P(1) is true
Assume P(k) is true for n = k.
∴ P(k+1) is true whenever p(k) is true.
∴ By the principle of Mathematical induction, p(n) is true for all n ε N.