Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
3.3k views
in Physics by (65.2k points)

A sealed container with negligible co-efficient of volumetric expansion contains helium (a monatomic gas) when it is heated from 200K to 400K, the average K.E. of helium atom is 

(A) Halved 

(B) Doubled 

(C) Unchanged 

(D) Increased by factor √2

1 Answer

+1 vote
by (70.8k points)
selected by
 
Best answer

The correct option (B) Doubled

Explanation:

Avg. KE = (3 / 2) KBT i.e. KE ∝ T 

Hence if temperature is doubled then KE will also get doubled.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...