Question

In a chemistry laboratory, a student found a bottle labeled ‘Acid’. As it was a solid, was curious to find out what it is. She weighed 0.42 g of this and made a solution of it and titrated it with 0.17 M NaOH solution. The volume of NaOH required to obtain the end point was 33.8 mL. If the molecular formula of the acid is C₆H₁₀O₄, find out the n umber of protons per acid molecule that take part in the reaction and the amount of acid required to neutralize 1 mole of alkali. 

(A) 1 proton and 73 g 

(B) 2 protons and 146 g 

(C) 1 proton and 46 g 

(D) 2 protons and 73 g

Answer 1

Correct option: (D) 2 protons and 73 g

Explanation: 

Let no. of neutralisable H⁺ be = n

So no. of gm equivalents of acid = (no. of moles) x (n)

Now for neutralization

no. of gm equivalents of NaOH = no. of gm equivalent of acid

Amount of acid to neutalise one mole of alkali will be