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At room temperature (27°C), the rms speed of the molecules of certain diatomic gas is found to be 1930 m/s. The gas is 

(A) O2 

(B) Cℓ2 

(C) H2 

(D) F2

1 Answer

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Best answer

The correct option (C) H2

Explanation:

Vrms = √(3RT/Mo)

MO = (3RT/Vrms2)

MO = [{3 × 8.314 × (273 + 27)}/{(1930)2}]

MO = 2 × 10–3 kg

As molar mass is 2 gm hence gas should be hydrogen H2

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