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Two circles x^2 + y^2 + px + py – 7 = 0 and x^2 + y^2 – 10x + 2py + 1 = 0 intersect each other orthogonally then the value of p is

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Two circles x2 + y2 + px + py – 7 = 0 and x2 + y2 – 10x + 2py + 1 = 0 intersect each other orthogonally then the value of p is 

(A) 1 

(B) 2 

(C) 3 

(D) 5

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Correct option  (B, C)

Explanation:

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