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in Olympiad by (66.0k points)

As shown in the grid figure given below, there is a foot rule of dimensions 12” x 3” kept on and above the principal axis of a small concave mirror of radius of curvature 24”. Distances from the pole of the mirror along the principal axis are marked. The 6” mark of the foot rule is at the center of curvature of the mirror.

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1/v + 1/u = 1/f & h1/h0 = - v/u

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