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\(\frac{\sqrt[6]2 \left[(625)^{3/5} \times (1024)^{-6/5} \div(25)^{3/5}\right]^{1/2}}{\left[(\sqrt[3]{128})^{-5/2}\right] \times (125)^{1/5}}\) \(\div \frac{(10^3)^2 \div (10^2)^3}{10^2)^3 \div(10^3)^2}\) equals

(a) \(\frac 15\)

(b) \(\frac 1{125}\)

(c) 1

(d) \(\frac 1{10}\)

1 Answer

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Best answer

Correct option is (c) 1

\(\frac{\sqrt[6]2 \left[(625)^{3/5} \times (1024)^{-6/5} \div(25)^{3/5}\right]^{1/2}}{\left[(\sqrt[3]{128})^{-5/2}\right] \times (125)^{1/5}}\) \(\div \frac{(10^3)^2 \div (10^2)^3}{10^2)^3 \div(10^3)^2}\)

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