\(\frac{\sqrt[6]2 \left[(625)^{3/5} \times (1024)^{-6/5} \div(25)^{3/5}\right]^{1/2}}{\left[(\sqrt[3]{128})^{-5/2}\right] \times (125)^{1/5}}\) \(\div \frac{(10^3)^2 \div (10^2)^3}{10^2)^3 \div(10^3)^2}\) equals
(a) \(\frac 15\)
(b) \(\frac 1{125}\)
(c) 1
(d) \(\frac 1{10}\)