Question

If V/t² = A√5 - B, find the dimensions of A and B.

Answer 1

\(\frac{V}{t^ 2}-A\sqrt{5}-B\)

Then,

\(B =\frac{V}{t^ 2}\)

\(B=\frac{[LT^{-1}]}{[T^ 2]^ 2}\)

B = [LT^-5]

And,

\(\frac{V}{t^ 2}=A\sqrt{5}\)

\(A=\frac{V}{t^ 2\sqrt{5}}\)

\(A=\frac{[LT^ {-1}]}{[T^ 2][L]^ {\frac{1}{2}}}\)

\(A=[L^ {\frac{1}{2}}T^ {-3}]\)