Correct option is (c) ac > bc
It is given that both a and b are positive and a > b.
But it is not given whether c is positive or negative.
Now
a > b
a ± c > b ± c
Also c2 > 0 for any real value of c.
Hence
\(\frac a{c^2} > \frac b{c^2}\)
However,
ac > bc is only true if C > 0
If c < 0
ac < bc