Correct option is (a) 1st offer
Let the cost price of the article = Rs 100.
FIRST CASE-
First discount = 20%.
So the first S.P. = Rs(100 − 20) = Rs 80.
Second successive discount = 10%.
So the second S.P. = Rs.80\(\left(1 - \frac{10}{100}\right)\) = Rs 72
Third successive discount = 5%.
So the third S.P. = Rs.72\(\left(1 - \frac{5}{100}\right)\) = Rs 68.4
SECOND CASE-
First discount = 15%.
So the first S.P. = Rs(100 − 15) = Rs85.
Second successive discount = 12%.
So the second S.P. = Rs.85\(\left(1 - \frac{12}{100}\right)\) = Rs 74.8
Third successive discount = 8%.
So the third S.P. = Rs.74.8\(\left(1 - \frac{8}{100}\right)\) = Rs 68.82
∴ The first offer is the better offer for the customer since the final S.P. is less than that of the second offer.