Question

O is the centre of a circle. There is a point P in the region of the circle. If PA = PB = PC where A, B and C are points on the circumference of the circle, then OP must be equal to:

(a) \(\frac{PA + PB + PC}{3}\)

(b) \(\frac{PA + PB + PC}{2}\)

(c) \(\frac{AB + BC}{2}\)

(d) zero

Answer 1

Correct option is (d) zero

Given, P is a point in the circle. A,B and C are the points on the circumference of the circle. 

and, PA = PB = PC

We know the distances of all the points from the centre to the circumference of the circle are equal.

Hence, P will be the center of the circle, coinciding with O.

Hence, OP = 0