Correct option is (d) 36
Area of the circumscribed circle of a square is double the area of the circle inscribed in it.
Area of the inscribed circle = π\((\frac a2)^2 \)
where, a = side of the square
\(\therefore 2\pi (\frac a2)^2 - \pi (\frac a2)^2 = 9 \pi\)
On solving we get, a = 6
∴ Area of the square = 62 = 36