Correct option is (d) 17 times
Let the length breadth and height of the cuboid be x, 2x and 3x units.
The dimensions after increase are \(x + \frac{100}{100}x, 2x + \frac{200}{100} \times 2x, 3x + \frac{200}{100} \times 3x\)
i.e., 2x, 6x and 9x
Original volume = x × 2x × 3x = 6x3
Increased volume = 2x × 6x × 9x = 108x3
∴ Increase in volume =108x3 − 6x3 = 102x3
= 17 × 6x3
= 17 × original volume