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A husband and a wife appear in a interview for two vacancies in the same post. The probability of husband’s selection is 1/7 and that of wife’s is 1/6. What is the probability that none of them will be selected.

(a) \(\frac 2{13}\)

(b) \(\frac 57\)

(c) \(\frac 1{42}\)

(d) \(\frac{30}{42}\)

1 Answer

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Best answer

Correct option is (d) \(\frac{30}{42}\)

P(none of them will be selected) = P(A) × P(B)

\(=\frac 67 \times \frac 56\)

\(=\frac {30}{42}\)

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