Correct option is (c) \(\frac{23}{25}\)
A → 80% & B → 60%
E = A solve the problem
F = B solve the problem
P(E) = \(\frac {80}{100} = \frac 8{10}\)
P(F) = \(\frac {60}{100} = \frac 6{10}\)
Required Probability,
\(P(E\cup F ) = 1 - P(\bar E) P(\bar F)\)
\(= 1 - \left(1 - \frac 8{10}\right) \left(1 - \frac 6{10}\right)\)
\(= 1 - \left(\frac 2{10} \times \frac 4{10}\right)\)
\(= \frac 11-\frac 2{25}\)
\(= \frac{25-2}{25}\)
\(= \frac{23}{25}\)