What is the value of sin60° / cos^2 45° - 3t an 30° + 5 cos 90°

Question

What is the value of \(\frac{\sin 60°}{\cos^245° }\) – 3 tan 30° + 5 cos 90°

(a) 1

(b) –1

(c) 2/5

(d) 0

Answer 1

Correct option is (d) 0

\(\frac{\sin60°}{\cos^245°} - 3\tan 30° + 5\cos 90°\)

\(= \cfrac{\frac {\sqrt 3}2}{\frac 12} - 3 \times \frac 1{\sqrt 3} + 5 \times 0\)  [Using the values of sin, cos and tan 's]

\(= \sqrt 3 - \sqrt 3 + 0\)

\(= 0\)