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in Trigonometry by (49.1k points)
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The value of 2√2 cos45°.cos 60° + 2√3 sin 30°.tan 60° – cos 0° is

(a) 1/3

(b) 3

(c) –3

(d) 0

1 Answer

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Best answer

Correct option is (b) 3

\(2\sqrt2 \cos 45° \cos60° + 2\sqrt 3 \sin 30° \tan 60° - \cos0° \)

\(= 2\sqrt 2 \times \frac 1{\sqrt 2} \times \frac 12 + 2\sqrt 3 \times \frac 12 \times \sqrt 3 - 1\)

\(= 1 + 3 - 1\)

\(= 3\)

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