Question around selection and probability

Question

Find the number of ways to select 6 numbers randomly from the first 25 numbers ( 1, 2, 3, 4, 5, ....., 25) such that the probability of selecting a multiple of 3 from the chosen numbers 2/3.

Answer 1

No. Of multiples of 3=8

Remaining no.=17

No. Of ways of selecting 2 multiples of 3=₈C²

no. Of ways of selecting remaining 1 no, =17

^{Total no. of ways =} ₈C² x 17 =476