Question

Angles of elevation of the top of a tower from three points (collinear) A, B and C on a road leading to the foot of the tower are 30°, 45° and 60° respectively. The ratio of AB to BC is

(a) √3 :1

(b) √3 : 2

(c) 1 : 2

(d) 2 : √3

Answer 1

Correct  option is (a) √3 :1

\(\frac{AB}{BC} = \frac{AP - BP}{BP - CP}\)    ......(i)

Let the height of the given tower

OP = h

Then, in rt. \(\Delta\)OAP,