Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
110 views
in Physics by (15 points)
edited by

A charge is placed at the centre of the line joining two points q and Q as shown in the figure . Find the ratio of charges Q and q.

Please log in or register to answer this question.

1 Answer

0 votes
by (45.4k points)

For the system to be in equilibrium net force on each charge should be zero.

Net force on charge q at the right, due to other two charge should be zero.

\(F_q=\frac{kQq}{x^ 2}+\frac{kq^ 2}{(2x)^ 2}=0\)

\(\frac{kQq}{x^2}=\frac{-kq^ 2}{4x^ 2}\)

\(\frac{Q}{q}=\frac{-1}{4}\)

No related questions found

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...