Question

An electric dipole is formed by two charges +q and –q located in xy-plane at (0, 2) mm and (0, −2) mm, respectively, as shown in the figure. The electric potential at point P(100, 100) mm due to the dipole is V₀. The charges +q and –q are then moved to the points (−1, 2) mm and (1, −2) mm, respectively. What is the value of electric potential at P due to the new dipole?

(A) \(\frac{V_0}4\)

(B) \(\frac{V_0}2\)

(C) \(\frac{V_0}{\sqrt 2}\)

(D) \(\frac{3V_0}4\)

Answer 1

Correct option is (B) \(\frac{V_0}2\)