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in Physics by (48.0k points)
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A particle of mass m is moving in the xy-plane such that its velocity at a point (x, y) is given as \(\vec v = \alpha (y\hat x + 2x\hat y)\), where α is a non-zero constant. What is the force F acting on the particle?

(A) \(\vec F = 2m\alpha^2(x \hat x + y\hat y)\)

(B) \(\vec F = m\alpha^2(y \hat x + 2x\hat y)\)

(C) \(\vec F = 2m\alpha^2(y \hat x + x\hat y)\)

(D) \(\vec F = m\alpha^2(x \hat x +2 y\hat y)\)

1 Answer

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by (49.1k points)
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Best answer

Correct option is (A) \(\vec F = 2m\alpha^2(x \hat x + y\hat y)\) 

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