Join Sarthaks eConnect Today - Largest Online Education Community!
0 votes
21 views
asked in Olympiad by (70.6k points)

A student titrated a mixture of NaHCO3 and Na2CO3 against a standard solution of HCI. He pipetted out a certain volume of mixture and added phenolphthalein indicator. The pink solution changed to colourless after addition of x mL of HCI. To the same solution he added methyl orange indicator and continued the titration. The end point with methyl orange indicator was obtained after addition of y mL HCI. The volume of HCI required for complete neutralization of Na2CO3 is _________ . 

(a) 2 x 

(b) x/2 

(c) y 

d) y - x

1 Answer

+1 vote
answered by (70.1k points)
selected by
 
Best answer

Correct option: (a) 2 x

Explanation:

In presence of phenolphthalein indicator, equivalents of HCl = 1/2  equivalents of Na2O3.

So 1 eq. of Na2CO3 required = 2x ml of HCl.

Happy Diwali Wishes

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

Categories

...