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Two uniform identical rods each of mass M and length l are joined to form a cross

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Two uniform identical rods each of mass M and length l are joined to form a cross as shown in figure (10-W15). Find the moment of inertia of the cross about a bisector as shown dotted in the figure.

please solve it !

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2x1/12 ml2 sin245 = ml2/12

So, moment of inertia of the cross about bisector is I = ml2/12

by (10 points)
Why did u use sin²45 in the solution
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