Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.1k views
in Olympiad by (71.4k points)

Two helicopters X and Y are stationary at a distance of 80 m from each other and 10 m above the surface of sea (near the Antarctic). The two helicopters have sound detectors. Helicopter X is stationary, vertically above a 50 m thick block of ice. (For the purpose of calculation, the vertical section of the block can be considered as rectangle). A Blue whale (W) is stationary vertically below X and 50 m below the water surface in such a way that there is no ice in the line of sight between Whale W and helicopter Y. This line of sight intersects water surface at point M. 

Whale W gives out a call (sound) which is detected by X. Y received the same sound 0.07 seconds after X received it. (For practical purpose, helicopters are considered to be point objects). 

(i) How much height of ice is floating above the surface of sea ? 

(ii) What is the distance YM and YW ?

(iii) What is the time taken for the sound to travel from W to Y after W makes the sound ?

(iv) What is the time taken for the sound to travel from W to X ? 

(v) What is the velocity of sound in the ice ?

1 Answer

+1 vote
by (71.3k points)
selected by
 
Best answer

height of ice block outside the water = 9 % of 50 m = 4.5 m

Since density of ice = 910 kg/m3

& density of water = 1000 kg/m3 

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...