Question

In Young’s double slit experiment, the distance between the slits d is equal to 5λ, where λ is the wavelength of the monochromatic light used in the experiment. Then intensity of the light in front of one of the slits on a screen at a distance of D = 10 d would be approximately : 

(a) I_max/2

(b) 3/4I_max 

(c) I_max 

(d) I_max/4

Answer 1

Correct option: (a) I_max/2

Explanation: 

Corresponding phase difference would be