Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
1.3k views
in JEE by (35 points)

The solution to the differential equation (2xy+x2y+y3/3)dx +(x2+y2)dy=0 is

(a) x2yex + (y3/3)ex =c

(b) x2yex - (y3/3)ex =c

(c) x2y2ex + (y3/3)ex =c

(d) xy2ex + (y3/3)ex =c

by (194 points)
reshown by
+1
Are you sure you'd correctly typed the differential equation?
by (35 points)
Yes I am really sure about the question. The source where I referred had a solution to this question by doing partial derivative and then solving. I asked the same question here in the hope that I would get an alternate solution instead of partial derivative. Please help me as quick as possible. If you have further doubts, please kindly refer 2018 edition of JEE ADVANCED EXPLORER by MTG
by (35 points)
Anybody Please help me out..

Please log in or register to answer this question.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...