Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
686 views
in JEE by (35 points)

Figure shows two capacitor connected in series and joined to a battery. The graph shows the variation in potential as one moves from left to right on the branch containing the capacitors.

Please log in or register to answer this question.

1 Answer

+1 vote
by (20.4k points)

Correct Answer: C

Explanation :

According to graph we can say that potential difference across the capacitor 

C1 is more than that across C2. Since charge Q is same i.e., 

Q=C1V1=C2V2

=> C1/C2=V2/V1

=> C1<C2    (V1>V2).

No related questions found

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...