Sarthaks APP
+1 vote
in Olympiad by (182 points)
edited by

need solution for 41st  question

The greater and least resultant of two forces are 7N and 3N respectively. If each of the force is increased by 3N and applied at 60 degree. The magnitude of the resultant is

1 Answer

+1 vote
by (29.5k points)
Best answer

Let the two forces be x and y

Greatest resultant ( parallel cosz=1) = x+y = 7N ------------(1)

Least Resultant ( antiparallel cosz= -1) = x-y = 3N -------------(2)

Solving equation (1) and (2) we get  x =5N, y =2N

Each force is increased by 3N

Therefore x = 8N, y = 5N

Resultant vector = ( x2 + y2 +2xycos60o)1/2

= (64 + 25 + 2*8*5*1/2)1/2

= √129

Related questions

+1 vote
2 answers
asked Jun 9, 2017 in Olympiad by RAJEEV R (182 points)
+1 vote
2 answers
asked Jun 8, 2017 in Olympiad by RAJEEV R (182 points)
0 votes
1 answer
asked Aug 8, 2020 in Kinematics by Sunil Kumar BN (25 points)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.