From the question 11th, **For N=1(plus or minus) , the magnitude of force vector will be F and direction is the vector itself. **

For any other N , the answer will be 0

Explanation:

put N=2

You get vectors 180 deg. apart , which will cancel each other out( like on positive x axis and negative x axis)

Put N=3

You get vectors which are 120 deg apart, looks something like this ( only see the figure on that page)

But vectors can be displaced , so can also displace it to make a triangle (equilateral triangle) , by doing so you will realize that , by walking along the vector you will end up on same position from where you have started. Which means net vector is 0 .

This theorem is true for all closed shapes like triangle , square, pentagon , hexagon etc.

For N=4

Vector points towards the vertices of square

For N=5

Vector points towards the vertices of pentagon

Than

Hexagon ...........so on

**Hence the resultant vector will be 0 if it is pointing to the vertices of a symmetric and closed figure**