Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.3k views
in Physics by (69.2k points)

A symmetric concave lens of focal length 24 cm is now placed in contact with the convex lens and the object is brought back to its original position. The image formed will be 

(a)  a real one with a magnification 4 

(b)  a real one at a distance of 40 cm 

(c)  a virtual one at a distance of 120 cm 

(d)  a virtual one with a magnification 2.5

1 Answer

+1 vote
by (59.7k points)
selected by
 
Best answer

Correct option  (a) a real one with a magnification 4

Explanation:

Focal length of the convex lens : f1 = 12 cm

Focal length of the concave lens : f2 = 24 cm

Effective focal length of the combination : 

So the image formed is real with a magnification of 4.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...