Correct option (2) (3/4, 7/4)
Explanation:
y2 = 4x … (i)
x2 + y2 = 5 ….(ii)
for point of intersection x2 + 4x – 5 = 0
(x + 5) (x – 1) = 0
x = – 5 x =1
not possible y = ± 2
Point in IQ (1, 2)
Tangent at (1, 2)
2y = 4(x + 1/2)
y = x + 1
point (3/4, 7/4) lies on tangent