Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
50.2k views
in Chemistry by (69.5k points)

At 300 K and 1 atmospheric pressure, 10 mL of a hydrocarbon required 55 mL of O2 for complete combustion, and 40 mL of CO2 is formed. The formula of the hydrocarbon is : 

(1) C4H7Cl 

(2) C4H6 

(3) C4H8 

(4) C4H10

1 Answer

+1 vote
by (69.0k points)
selected by
 
Best answer

Correct option (2) C4H6

Explanation:

Hence. 1 mL of hydrocarbon = x mL of CO2 is produced

Hence the compound is C4H6

by (15 points)
Atleast give proper explanation

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...