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A uniform cable of mass ‘M’ and length ‘L’ is placed on a horizontal surface such that its (1/n)th  part is hanging below the edge of the surface. To lift the hanging part of the cable upto the surface, the work done should be -

(1) nMgL

(2)  MgL/2n2

(3)  2MgL/n2

(4)  MgL/n2

1 Answer

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Best answer

Correct option  (2)  MgL/2n2

Explanation:

Work done against gravity 

= mgh

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