Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
42.9k views
in Chemistry by (74.4k points)

The minimum amount of O2(g) consumed per gram of reactant is for the reaction : (Given atomic mass : Fe = 56, O = 16, Mg = 24, P = 31, C = 12, H = 1)

(1) 4 Fe(s) + 3 O2(g) → 2 Fe2O3(s) 

(2) P4(s) + 5 O2(g) → P4O10(s) 

(3) C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l) 

(4) 2Mg(s) + O2(g) →MgO(s)

1 Answer

+1 vote
by (69.6k points)
selected by
 
Best answer

Correct option (1) 4 Fe(s) + 3 O2(g) → 2 Fe2O3(s) 

Explanation:

Which is least amount  

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...