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The speed of a projectile at the highest point becomes 1/√2 times its initial speed. The horizontal range of the projectile will be

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The speed of a projectile at the highest point becomes 1/√2 times its initial speed. The horizontal range of the projectile will be

(a) u2/g

(b) u2/2g

(c) u2/3g

(d) u2/4g

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1 Answer

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Best answer

Correct Option u2/g

Explanation:

Velocity at the highest point is given by

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