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Using divergence theorem, evaluate ∫∫s vector F.ndS where vector F = x3i + y3j + z3k and S is the surface of the sphere x2 + y2 + z2 = a2.

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∴ by divergence theorem, we get

Since, V is the volume of the sphere we transform the above triple integral into spherical polar coordinates (r, θ, φ).

For the spherical polar coordinates (r, θ, φ), we have

x2 + y2 + z2 = r2 and dx dy dz = dV

∴ dV = r2sin θ dr dθ d φ

Also, 0 ≤ r ≤ a, 0 ≤ θ ≤ π and 0 ≤ φ ≤ 2π

Therefore (1) reduces to,

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