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The percentage by volume of C3H8 in a mixture of C3H8, CH4 and CO is 36.5. Calculate the volume of CO2 produced when 100 mL of the mixture is burnt in excess of O2

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Let a mL, b mL and c mL be volumes of C3H8, CH4 and CO respectively in 100 mL given simple, then 

a + b + c = 100 and a = 36.5 

Now CO2 is formed as a result of combustion of mixture.  

∴ Vol. of CO2 formed = 3a + b + c = 3 x 36.5 + (100 - 36.5) = 173 mL

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