Question

4 mole of MgCO₃ is reacted with 6 moles of HCl Solution. Find the volume of CO₂ gas produced at STP. The reaction is MgCO₃ + 2HCl → MgCl₂ + CO₂ + H₂O 

Answer 1

From the reaction MgCO₃ + 2HCl → MgCl₂ + CO₂ + H₂O 

There should be one limiting reagent. 

To find the limiting reagent, divide the given moles by stoichiometric coefficient.

∴ moles of CO₂ produced = 3 moles 

∴ volumes of CO₂ produced at S.T.P, = 3 x 22.4 = 67.2 L