Question

27.6 g of K₂CO₃ was treated by a series of reagents so as to convert all of its carbon to K₂Zn₃ [Fe(CN)₆]₂. Calculate the weight of the product.

Answer 1

Since C atoms are conserved, applying POAC for C atoms, 

Moles of C in K₂CO₃ = moles of C in K₂ Zn₃ [Fe(CN)₆]₂ 

1 x mole of K₂CO₃ = 12 x moles of K₂ Zn₃ [Fe(CN)₆]₂ 

[mol. wt. of K₂CO₃ = 138 and mol. wt. of K₂ Zn₃ [Fe(CN)₆]₂ = 698]