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A 150 mL 0.25 M NaCl Solution, 250 mL 0.45 M CaCl2 Solution and a 100 mL 0.60 M AlCl3 Solution are mixed together and diluted to a final volume of 750 mL by adding enough water. Determine molarity of chloride ion (Cl-) in Solution assuming that all three salts are completely soluble as well as completely dissociated.

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First we need to calculate total mmoles of Cl- from the three salt Solutions: 

mmoles of Cl- ion from NaCl = 37.5 

mmoles of Cl- ion from CaCl2 = 2 x 112.5 = 225 

mmoles of Cl- ion from AlCl3 = 3 x mmoles of AlCl3 = 3 x 60 = 180 

mmoles of Cl- in final Solution = 37.5 + 225 + 180 = 442.5

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