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If a directrix of a hyperbola centred at the origin and passing through the point (4, –2√3 ) is 5x = 4√5 and its eccentricity is e, then :

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If a directrix of a hyperbola centred at the origin and passing through the point (4, –2√3 ) is 5x = 4√5 and its eccentricity is e, then :

(1)   4e4 – 24e2 + 27 = 0 

(2)   4e4 – 24e2 + 35 = 0

(3)   4e4 – 12e2 – 27 = 0

(4)   4e4 + 8e2 – 35 = 0 

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Correct option  (2) 4e4 – 24e2 + 35 = 0

Explanation:

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