Question

The perimeter of a rectangle is 40 cm. The length of the rectangle is more than double its breadth by 2. Find length and breadth. 

Answer 1

Let length of rectangle be x cm and breadth be y cm.

From first condition - 2(x + y) = 40 

x + y = 20 . . . (I) 

From 2nd condition - 

x = 2y + 2

x - 2y = 2 . . . (II)

Let’s solve eq. (I), (II) by determinant method

x + y = 20 

x - 2y = 2

Length of the rectangle is 14 cm and breadth is 6 cm.