Question

An elliptical cavity is carved within a perfect conductor. A positive charge q is placed at the center of the cavity. The points A and B are on the cavity surface as shown in the figure. Then 

(A) Electric field near A in the cavity = electric field near B in the cavity. 

(B) Charge density at A= potential at B. 

(C) Potential at A=potential at B. 

(D) Total electric field flux through the surface of the cavity is q/ε₀.

Answer 1

Correct option (C, D)

Explanation: 

Using Gauss’s Law

It electric field is same at all the points of a surface, it is knows as equipotential surface.