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An AP consists of 50 terms of which 3rd term is 12 and the last term is 106. Find the 29th term.

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Solution: 12 = a + 2d
106 = a + 49d
So, 106-12 = 47d
Or, 94 = 47d
Or, d = 2
Hence, a = 8
And, n29 = 8 + 28x2 = 64

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