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The 17th term of an AP exceeds its 10th term by 7. Find the common difference?

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The 17th term of an AP exceeds its 10th term by 7. Find the common difference.

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Solution: n7 = a + 6d
And, n10 = a + 9d
Or, a + 9d – a – 6d = 7
Or, 3d = 7
Or, d = 7/3

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